WebReduce this equation to standarm form 9x^2-4y^2+36x-16y-16=0. Find also the coordinates of the center, foci, and vertices. Draw also the asymptote and sketch the graph of the equation. Answer by rothauserc (4718) ( Show Source ): You can put this solution on YOUR website! 9x^2 -4y^2 +36x -16y -16 = 0 this is the equation of a hyperbola Web頂点 9x^2-4y^2+54x+16y+66=0の詳細な解答
Hyperbola Calculator - Symbolab
WebVertices of a Hyperbola. The points at which a hyperbola makes its sharpest turns. The vertices are on the major axis (the line through the foci). See also. Vertex, directrices of a … WebThis calculator will find either the equation of the hyperbola from the given parameters or the center, foci, vertices, co-vertices, (semi)major axis length, (semi)minor axis length, latera recta, length of the latera recta (focal width), focal parameter, eccentricity, linear eccentricity (focal distance), directrices, asymptotes, x-intercepts, … tasmanian landscape artists
Hyperbola Calculator - eMathHelp
Web9 (x 2 -2x)+16 (y 2 +6y)= -9 Now we take the number in from of the first degree term, divide it by 2 and square it. For x, -2 divided by 2 is -1, squared is 1. For y, 6 divided by 2 is 3, squared is 9. We must add each of these values to both sides of the equation. WebTranscribed image text: An equation of a hyperbola is given. 9x2 - 16y2 = 1 (a) Find the vertices, foci, and asymptotes of the hyperbola. (Enter your asymptotes as a vertex (x, y) = (smaller x-value) vertex (x, y) = (larger x-value) focus (x, y) = (smaller x-value) focus (x, y) = (1 (larger x-value) asymptotes (b) Determine the length of the ... WebHyperbola. Center; Axis; Foci; Vertices; Eccentricity; Asymptotes; Intercepts New; Trigonometry. ... foci\:\frac{(x-1)^2}{9}+\frac{y^2}{5}=100; vertices\:9x^2+4y^2=36; eccentricity\:16x^2+25y^2=100; ellipse-equation-calculator. en. image/svg+xml. Related Symbolab blog posts. Practice, practice, practice. Math can be an intimidating subject ... tasmanian land conservancy trust