Webno the formula 1/f=1/di- 1/do is correct, because it is based on the sign covention for lenses where object distance (do) is always taken as negative for all real objects, but sal's formula is also not wrong because he did not stick to the sign convention ( he took the object distance as positive) WebAs a demonstration of the effectiveness of the lens equation and magnification equation, consider the following sample problem and its solution. Sample Problem #1 A 4.00-cm tall light bulb is placed a distance of 45.7 cm from a double convex lens having a focal length of 15.2 cm. Determine the image distance and the image size.
Solved Given f = 5 cm, so = 3 cm, ho = 2 cm 1. Convex lens - Chegg
WebIf both ho and hi are positive, it means that the object is above the principal axis. This is possible only if the image is virtual and erect. For negative magnification, hi and ho are of different signs, If ho is positive then hi is negative and if hi is negative then we can conclude that the image is formed below the principal axis. Web514 other terms for magnification- words and phrases with similar meaning custodial trading accounts for kids
Magnification/Focal Length Physics Forums
WebMagnification (m) = h/h’ And h’ is the image height and h is the object height. Magnification can also be related to the image distance and object distance; therefore it … WebThen use hi / ho = - di / do where ho = 5 cm, do = 45 cm, and di = 22.5 cm A magnified, inverted image is located a distance of 32.0 cm from a concave mirror with a focal length of 12.0 cm. Determine the object distance and tell whether the image is real or virtual. WebApr 11, 2024 · What significance does the negative sign give to a value for magnification? Question. Transcribed Image Text: Single lens f₁ = 55 mm radius of circle,h. =__20 Object ... no = 2cm 20mm M hi/ho How does your measure values of the image distance p, compare to the calculated value? lauq bas gt 7) 0819 tis queda a litnu anal sl the not ad ... custodial training checklist